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  1. (d);6332180996321033282
  2. (a);   6332180996321033283 1
  3. (a);6332180996321033290
  4. (b); 6332180996321033291
  5. (c); 6332180996321033293 1
  6. (b); Obviously, Z is facing south
                         6332180996321033294
  7. (c); 6332180996321033301
    Clearly, Alok is in South – West direction from starting point.
  8. (b); As shown in Fig. the man initially faces in the direction OP. On moving 90° clockwise the man faces in the direction OQ. On further moving 135° anticlockwise, he faces in the direction OR, which is West.
    6332180996321033312
  9. (d); As shown in Fig. the man initially faces in the direction OP. On moving 90° clockwise, he faces in the direction OX. On further moving 180° anticlockwise, he faces in the direction OY. Finally, on moving 90° anticlockwise, he faces in the direction OZ, which is South-east.
    6332180996321033335
  10. (b); As shown in Fig. the man initially faces towards east i.e., in the direction OA. On moving 100° clockwise he faces in the direction OB. On further moving 145°clockwise, he faces in the direction OC, Clearly, OC makes an angle of (145°-100°) i.e. 45° with OA and as such points in the direction North-east.
    6332180996321033353
  11. (b); The movements of Kishankant are as shown in Fig. (A to B, B to C and C to D).
    AC = (AB-BC) =(10-6) km = 4 km
    Kishankant’s distance from starting point A
    = AD Capture = 5km
    So Kishankant is 5 km to the North-east of his starting point.

    6332180996321033354
  12. (d); The movements of Gaurav are as shown in Fig. Clearly, Gaurav’s distance from his initial position 
    P = PX = (PS + SX)
    = (QR + SX) = (40 + 20)m = 60
    6332180996321033359
  13. (c); The movements of Radha are as shown in figure.
    Clearly, Radha’s distance from the starting point O = OD = (OC – CD) = (AB – CD) = (14 – 4)m = 10 m
    6332180996321033370
  14. (c); The movements of rat from A to G are as shown in Fig.
    Clearly, it is finally walking in the direction FG, ie North.6332180996321033387
  15. (d); The movements of the person are from A to F, as shown in figure.
    Clearly, the final position if F which is to the North-east of the starting point.
    6334432796134720189
  16. (a); The movements of Rohit are as shown in fig.
    Rohit’s distance from starting point A
    = AE = (AD + DE) = (BC + DE) = (20 + 15) m = 35 m.
    Also, E is to the East of A
    6334432796134720220
  17. (c); The movements of Sachin are as shown in figure
    (P to B, B to C, C to D and D to Q).
    Clearly, distance of Q from P
    = PQ = (DQ – PD) = (DQ –BC) = (40 – 30) m = 10 m.
    Also, Q is to the West of P. So, Q is 10 m West of P. 
    6334432796134720232
  18. (c); The movements of the man are as shown in Fig.
    (A to B, B to C, C to D and D to E)
    Clearly, DF = BC = 5 km
    EF= (DE-DF) = (9-5) km = 4 km
    BF = CD = 2 km
    AF = AB + BF = AB + CD = (1 + 2) km = 3 km
    Man’s distance from starting point A = AE
    Capture 1
    6334432796134720237

  19. (c); The movements of Lokesh are as shown in Fig.
    (A to B, B to C, C to D and D to E)
    Clearly, his final position is E which is to the North of his house at A.
    Capture 2

  20. (a); Let X and Y be two buses.
    WhatsApp Image 2024 10 03 at 12.54.04
    Bus X travels along the path PA, AB, BC, CD.
    Now, AD = BC = 25km
    So, PD = PA + AD = 50km
    Bus Y travels 35 km upto E
    – Distance between two buses = PQ – (PD + QE)
    = [150 – (50+35)] = 65 km
  21. (a); Clearly, the route of Sohan is as shown in the diagram given below:
    Here, XB = XY – YB = XY – AZ (∴ YB = AZ)
    = 8km – 7km =1km
    WhatsApp Image 2024 10 03 at 12.59.57
  22. (d); From the figure given below, Raj is finally in the North – West direction from the starting point.
    download 1
  23. (d); From the figure, it is clear that Alok is in the South-East direction with reference to starting Point Q.
    download 2
  24. (d); WhatsApp Image 2024 10 03 at 13.20.09
  25. (a); Capture 3
    Finally he is facing North direction.
  26. (a);      direction and distance type 2 distance only b26
    Clearly the distance between A and B = 1km

  27. (b);      direction and distance type 2 distance only b27

  28. (b);         download 3

    Let his starting point is S.
    AB = SC =15 m, BC = AS = 15km
    BD – BC = 35 – 15 = 20 km
    SD = √SC2+√CD2 = √152+√202
    = √225+400 = √625 = 25km

    (29 – 30)
    Capture 4
  29. (d); Total distance walked by the boy.
    = 40+50+60+80=230m
  30. (c); CE = √BC2 + √BE2 = √8500 = 92.19m
  31. (a); LUC VER REAS C37 E01 003 S01
  32. (d); The movements of the person are from A to F, as shown in figure.
    Clearly, the final position if F which is to the North-east of the starting point.
    Capture 5

  33. (a); The movements of Aditya are shown in figure from A to G. Clearly,
    Gopal is finally walking in the direction FG i.e., North.
                  download 4
  34. (c); The movements indicated are as shown in figure.
    Thus, the final movements in the direction indicated by DE, which is east.
      Capture 6
  35. (d); The movements is shown in figure— Clearly, EB
    = DC = 40 m.
    So, distance from the starting point A = (AB – EB) = (75 – 40)m = 35m
    Capture 7
  36. (b); : The movements is as shown in figure.
    AC = (AB – BC) = (10 – 6) km = 4 km.
    Clearly, D is to the North-east of A.
    So, Kunal’s distance from starting point A = AD
    = √AC2 + √CD2 = “ √42 + √32 = √25 = 5 km.
    So, it is 5 km to the North-east of his starting point.
        Capture 8
  37. (a); The movements of Rohan are as shown in figure
    (A to B, B to C, C to D and D to E). Clearly, AD =
    BC = 2 km
    So, required distance = AE = (DE – AD) = (3 – 2)
    = 1 km. 
       Capture 9
  38. (d); The movements of Manick are as shown in figure (A to B, B to C and C to D). Clearly, ABCD is a rectangle and so AD = BC = 20m. Thus, D is 20m to the west of A.
    download 5
  39. (b); The movements of Namita are shown in figure (A to B, B to C, C to D and D to E). Clearly, Namita’s distance from his initial position = AE = (AB + BE) = (AB + CD) = (14 + 10) m = 24 m. 
       Capture 10
  40. (b); Clearly, DC = AB + FE. So, F is in the line with A. Also, AF = (BC – DE) = 5 m. So, the man is 5 metres away from his initial position.
      download 6
  41. (c); The movements of Radha are as shown in figure.
    Clearly, Radha’s distance from the starting point O = OD = (OC – CD)
    = (AB – CD) = (14 – 4)m = 10 m.
      download 7
  42. (c); The movements of Amit are shown in figure (P to Q, Q to R and R to S). Clearly, his final position is S which is to the South-east of the starting point P.
        download 8
  43. (b); By Pythagorean Theorem:
    AD = √92 + √122
    AD = √81 + √144
    AD = √225
    AD = 15 km
           download 9
  44. (a); The movements of the girl are as shown in figure (A to B, B to C, C to D, D to A).
    Clearly, she is finally moving in the direction DA i.e., Northeast.
                Capture 11
  45. (b); The movements of Sanjeev from A to F are as shown in Figure Clearly,
    Sanjeev’s distance from starting point A
    = AF = (AB + BF) = AB + ( BE – EF ) = AB + (CD – EF)
    = [10 + (20 – 10)] m = (10 + 10) m = 20 m.
    Also, F lies to the South of A. So, Sanjeev is 20 meters to the south of his starting point.
          LUC VER REAS C37 SLV 006 S01
  46. (b); The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E). So, Kashish’s distance from his original position A = AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.
            354938 209328 ans
  47. (d); The movements of the man are as shown in figure. So, Man’s distance from initial position A = AE = (AB + BE) = (AB + CD) = (30 + 20) m = 50 m.
                4a15feba 35b1 4943 9dfe 439a0ac234cf lg
  48. (a); The movements of Rohit are as shown in the figure. So, Rohit’s distance from starting point A = AE = (AD + DE) = (BC + DE) = (20 + 15) m = 35 m.
    Also, E is to the East of A
          Capture 12
  49. (c); The movements of Sachin are as shown in figure (P to B, B to C, C to D and D to Q). Clearly, distance of Q from P = PQ = (DQ – PD) = (DQ – BC) = (40 – 30) m = 10 m. Also, Q is to the West of P. So, Q is 10 m West of P.
        Capture 13
  50. (d); The movements of Ramakant are as shown in figure. Clearly, he is finally walking in the direction DE i.e., West. 
         Capture 14
  51. (d); As shown in figure, the man initially faces in the direction OA. On moving 135° anticlockwise, he faces in the direction OB. On further moving 180° clockwise, he faces in the direction OC, which is South – West.
    LUC VER REAS C37 E01 055 S01
  52. (b); As shown in figure, the man initially faces in the direction OP on moving 90° clockwise, the man faces in the direction OQ. On further moving 135° anti clockwise, he faces in the direction OR, which is West.
      Capture 15
  53. (d); ARH TST OF REAS VR C07 E01 001 S01
  54. (b); As shown in fig, the river flows eastwards from A towards B, turns left and follows a semi-circular path to reach C where it turns left and flows east wards towards D.
    6302be05 8f42 4cb3 8edc 877b5d853cad lg
  55. (c); The movements are as indicated in figure(O to A, A to B and b to C). Clearly, C lies to the South-West of O.
    1572113 fb1ef7f5 cbdc 4235 9fe5 b1f8d1ca8915 lg
  56. (b); As shown in the figure, the man initially faces towards east i.e., in the direction OA. On moving 100 clockwise. he faces in the direction OB. On further moving 145 anticlockwise, he is facing the direction OC. Clearly, OC makes an angle of (145100) i.e. 45 with OA and so, the man faces the direction North-east.
    content 1
  57. (c); The movements of rat from A to G are shown in figure. Clearly, it is finally walking in the direction FG i.e., North.
    30202 explanation image
  58. (b); The movements of Maya from T to R are as shown in figure.
    Capture 16
    RT = √(RV)2+√(TV)2 = √16 + √9 = 5ft
  59. (b); ARH TST OF REAS VR C07 E01 013 S01
  60. (c); Capture 17

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Dhalendra Kothale

Dhalendra Kothale

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